题目: 题解:
class Solution:def lexicalOrder(self, n: int) -> List[int]:ans [0] * nnum 1for i in range(n):ans[i] numif num * 10 < n:num * 10else:while num % 10 9 or num 1 > n:num // 10num 1return ans
一、原题
链接:Training on Simple Fun #352: Reagent Formula | Codewars Now we will confect a reagent. There are eight materials to choose from, numbered 1,2,..., 8 respectively. We know the rules of confect: You are given a integer array formula…